
Statistical Methods with R
Unit B · Chapter 05 · Lecture 05a
Developed by Jeffrey M. Girard
Statistical Hypotheses
NHST Logic
NHST Nuts and Bolts
p-values and Pragmatics
Imagine that we study nutrition and obesity
Participants really like a brand of “low sugar” cereal
The label claims that it only contains 3 g of sugar per serving
However, we think this may be false advertising!
We buy a sample of 20 cereal boxes from various stores
We measure the amount of sugar per serving in each box
Is 3 g a reasonable estimate of the population mean?
H_1 is a “one-sided” and H_2 is a “two-sided” hypothesis.
In null hypothesis significance testing (NHST), the null hypothesis is the defense and the alternative hypothesis is the prosecution
The statistical test is the judge and jury (makes the decision)
NHST helps protect the null hypothesis from researchers who are incentivized to disprove it.
| Retain H_0 | Reject H_0 | |
|---|---|---|
| H_0 is True | Correct Retain | Type I Error |
| H_0 is False | Type II Error | Correct Reject |
| Retain H_0 | Reject H_0 | |
|---|---|---|
| H_0 is True | 1-\alpha | \text{[I] }\alpha |
| H_0 is False | \text{[II] }\beta | 1-\beta |
How far from zero is too far? When do we reject the null?
We look at the sampling distribution of \Delta under the null
We can use this to make our statistical decision
To set \alpha=.05, we reject the null if the test statistic is outside the middle 95% of its null sampling distribution
The math becomes easier if we standardize the test statistic by dividing it by its standard error
z_{\bar{x}} = \frac{\bar{x} - \mu_0}{\sigma / \sqrt{n}} \\ z_{\bar{x}} \sim \mathcal{N}(0, 1)

Critical values: |z_{\bar{x}}| > 1.96 (i.e., it falls in the red regions)
This z-test is rarely used because \sigma is rarely known
Instead, we estimate \sigma using s and use the t-test
With a small sample, the critical values are now higher
t_{\bar{x}} = \frac{\bar{x} - \mu_0}{s / \sqrt{n}} \\ t_{\bar{x}} \sim t(n-1, 0, 1)

Critical values: |t_{\bar{x}}| > 2.09 (i.e., it falls in the red regions)
Imagine H_0 is true (\mu=3) and we collect the following sample of 20 cereal boxes


|t_{\bar{x}}|<t_{crit}: \text{Retain }H_0
Imagine H_0 is false (\mu=4) and we collect the following sample of 20 cereal boxes


|t_{\bar{x}}|>t_{crit}: \text{Reject }H_0
Correct p-value Definitions
The p-value is the smallest \alpha value that would reject the null hypothesis.
The p-value is the probability of observing a test statistic at least as extreme as ours, if the null hypothesis were true.
Wrong p-value Definition
The p-value is the probability that the null hypothesis is true.
| Notation | Stars | Translation | Decision |
|---|---|---|---|
| p ≥ .05 | Test was NOT significant at α=.05 | Retain Null | |
| p < .05 | * | Test was significant at α=.05 | REJECT Null |
| p < .01 | ** | Test was significant at α=.01 | REJECT Null |
| p < .001 | *** | Test was significant at α=.001 | REJECT Null |
t.test()model_parameters()fit1 <- t.test(sugar_null, mu = 3)
library(easystats)
model_parameters(fit1)
## One Sample t-test
##
## Parameter | Mean | mu | Difference | 95% CI | t(19) | p
## ------------------------------------------------------------------
## sugar_null | 3.09 | 3 | 0.09 | [2.96, 3.22] | 1.42 | 0.171
##
## Alternative hypothesis: true mean is not equal to 3One Sample t-test
Parameter | Mean | mu | Difference | 95% CI | t(19) | p
------------------------------------------------------------------
sugar_null | 3.09 | 3 | 0.09 | [2.96, 3.22] | 1.42 | 0.171
Alternative hypothesis: true mean is not equal to 3
“The mean sugar content per serving in our sample was 3.09 g, 95% CI: [2.96, 3.22], which was not significantly different from the 3 g stated on the label, t(19)=1.42, p=.171. Thus, we retain the null hypothesis that there are 3 g of sugar per serving.”
fit2 <- t.test(sugar_alt, mu = 3)
model_parameters(fit2)
## One Sample t-test
##
## Parameter | Mean | mu | Difference | 95% CI | t(19) | p
## ------------------------------------------------------------------
## sugar_alt | 4.02 | 3 | 1.02 | [3.65, 4.39] | 5.70 | < .001
##
## Alternative hypothesis: true mean is not equal to 3One Sample t-test
Parameter | Mean | mu | Difference | 95% CI | t(19) | p
------------------------------------------------------------------
sugar_alt | 4.02 | 3 | 1.02 | [3.65, 4.39] | 5.70 | < .001
Alternative hypothesis: true mean is not equal to 3
“The mean sugar content per serving in our sample was 4.02 g, 95% CI: [3.65, 4.39], which was significantly greater than the 3 g stated on the label, t(19)=5.70, p<.001. Thus, we reject the null hypothesis that there are 3 g of sugar per serving.”